I want to perform calculations for each company number in the column PERMNO of my data frame, the summary of which can be seen here:
> summary(companydataRETS)
PERMNO RET
Min. :10000 Min. :-0.971698
1st Qu.:32716 1st Qu.:-0.011905
Median :61735 Median : 0.000000
Mean :56788 Mean : 0.000799
3rd Qu.:80280 3rd Qu.: 0.010989
Max. :93436 Max. :19.000000
My solution so far was to create a variable with all possible company numbers
compns <- companydataRETS[!duplicated(companydataRETS[,"PERMNO"]),"PERMNO"]
And then use a foreach loop using parallel computing which calls my function get.rho() which in turn perform the desired calculations
rhos <- foreach (i=1:length(compns), .combine=rbind) %dopar%
get.rho(subset(companydataRETS[,"RET"],companydataRETS$PERMNO == compns[i]))
I tested it for a subset of my data and it all works. The problem is that I have 72 million observations, and even after leaving the computer working overnight, it still didn't finish.
I am new in R, so I imagine my code structure can be improved upon and there is a better (quicker, less computationally intensive) way to perform this same task (perhaps using apply or with, both of which I don't understand). Any suggestions?
As suggested by Joran, I looked into the library data.table
. The modifications to the code are
library(data.table)
companydataRETS <- data.table(companydataRETS)
setkey(companydataRETS,PERMNO)
rhos <- foreach (i=1:length(compns), .combine=rbind) %do%
get.rho(companydataRETS[J(compns[i])]$RET)
I ran the code as I originally had (using subset
) and once using data.table
, with the variable compns
comprising of only 30 of the 28659 companies in the dataset. Here are the outputs of system.time()
for the two versions:
Using subset
:
user........ system..... elapsed
43.925 ... 12.413...... 56.337
Using data.table
user....... system..... elapsed
0.229..... 0.047....... 0.276
(For some reason using %do%
instead of %dopar%
for the original code made it ran faster. The system.time()
for subset
is the one using %do%
, the faster of the two in this case.)
I had left the original code running overnight and it hadn't finished after 5 hours, so I gave up and killed it. With this small modification I had my results in less than 5 minutes (I think about 3 mins)!
EDIT
There is an even easier way to do it using data.table
, without the use of foreach
, which involves substituting the last line of the code above by
rhos <- companydataRETS[ , get.rho(RET), by=PERMNO]
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