Path to a file without basename [duplicate]

Question

How can I get the path of a file without the file basename?

Something like /a/path/to/my/file.txt --> /a/path/to/my/

Tried with .split() without success.

Answer 1

You can import os

>>> filepath '/a/path/to/my/file.txt' >>> os.path.dirname(filepath) '/a/path/to/my' >>>  

Answer 2

Use os.path.dirname(filename).