Passing XML string in the body of WCF REST service using WebInvoke

Question

I'm a newbie to WCF, REST etc. I'm trying to write a service and a client. I want to pass xml as string to the service and get some response back.

I am trying to pass the xml in the body to the POST method, but when I run my client, it just hangs.

It works fine when I change the service to accept the parameter as a part of the uri. (when I change UriTemplate from "getString" to "getString/{xmlString}" and pass a string parameter).

I'm pasting the code below.

Service

[ServiceContract]
public interface IXMLService
{
    [WebInvoke(Method = "POST", UriTemplate = "getString", BodyStyle=WebMessageBodyStyle.WrappedRequest, 
    RequestFormat = WebMessageFormat.Xml, ResponseFormat = WebMessageFormat.Xml)]

    [OperationContract]
    string GetXml(string xmlstring);
}

// Implementaion Code

public class XMLService : IXMLService
{
    public string GetXml(string xmlstring)
    {
        return "got 1";
    } 
}    

Client

string xmlDoc1="<Name>";        
xmlDoc1 = "<FirstName>First</FirstName>";
xmlDoc1 += "<LastName>Last</LastName>";
xmlDoc1 += "</Name>";

HttpWebRequest request1 = (HttpWebRequest)WebRequest.Create(@"http://localhost:3518/XMLService/XMLService.svc/getstring");
request1.Method = "POST";
request1.ContentType = "application/xml";
byte[] bytes = Encoding.UTF8.GetBytes(xmlDoc1);        
request1.GetRequestStream().Write(bytes, 0, bytes.Length); 

Stream resp = ((HttpWebResponse)request1.GetResponse()).GetResponseStream();
StreamReader rdr = new StreamReader(resp);
string response = rdr.ReadToEnd();

Could somebody please point out what's wrong in it?

Answer 1

Change your operation contract to use an XElement and the BodyStyle of Bare

[WebInvoke(Method = "POST", 
    UriTemplate = "getString", 
    BodyStyle = WebMessageBodyStyle.Bare,
    RequestFormat = WebMessageFormat.Xml, 
    ResponseFormat = WebMessageFormat.Xml)]
[OperationContract]
string GetXml(XElement xmlstring);

Additionally I suspect you client code should contain (note the first +=):

string xmlDoc1="<Name>";
xmlDoc1 += "<FirstName>First</FirstName>";
xmlDoc1 += "<LastName>Last</LastName>";
xmlDoc1 += "</Name>";

Answer 2

You still need to create a class:

public class Test
{

    public string xmlstring{ get; set; }

}

You can also use fiddler to check if the serialized XML could be passed as a parameter.