Passing variable through PHP exec

Question

I am using the php exec command to execute another file.

I am using the following:

 exec ('php email.php');

But I would wish to pass a variable called $body to "email.php" file through the exec command. How can I pass the variable through exec command?

Answer 1

Pass the argument:

exec('php email.php "' . addslashes($body) . '"');

Get it in email.php:

$body = stripslashes($argv[1]);

Answer 2

Use:

 exec ('php email.php firstparameter secondparameter thirdparameter');

You can also refer this : Command Line Manual