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In PHP is it possible to do something like this:
myFunction( MyClass::staticMethod ); so that 'myFunction' will have a reference to the static method and be able to call it. When I try it, I get an error of "Undefined class constant" (PHP 5.3) so I guess it isn't directly possible, but is there a way to do something similar? The closest I've managed so far is pass the "function" as a string and use call_user_func().
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It's generally a bad idea to depend on static methods because they make substitution (and therefore specialising or testing) difficult. It looks like what you have is 10 independent classes that all inherit from the same interface. But without explaining what those functions do, its impossible to say how to improve.
The static variable is used in the A and B classes, yet the method is inherited so it is actually the same code which is called. Until PHP 8.0, there would be a distinct static variable depending on which class is called.
To add a static method to the class, static keyword is used. They can be invoked directly outside the class by using scope resolution operator (::) as follows: MyClass::test(); Example: This example illustrates static function as counter.
The 'php way' to do this, is to use the exact same syntax used by is_callable and call_user_func.
This means that your method is 'neutral' to being
In the case of static methods, this means you should pass it as:
myFunction( [ 'MyClass', 'staticMethod'] ); or if you are not running PHP 5.4 yet:
myFunction( array( 'MyClass', 'staticMethod') ); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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