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Passing references to pointers in C++

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How do you pass references to a pointer?

Passing “pointer to a pointer” as a parameter to function The above problem can be resolved by passing the address of the pointer to the function instead of a copy of the actual function. For this, the function parameter should accept a “pointer to pointer” as shown in the below program: CPP.

Do pointers get passed by reference?

A pointer is an object itself. It can be assigned or copied to pass a reference to a pointer as a function parameter.

Can you have a reference to a pointer?

References to pointers can be declared in much the same way as references to objects. A reference to a pointer is a modifiable value that's used like a normal pointer.

Why are pointers used in passing parameters by reference?

In C++, variables are passed by reference due to following reasons: 1) To modify local variables of the caller function: A reference (or pointer) allows called function to modify a local variable of the caller function.


Your function expects a reference to an actual string pointer in the calling scope, not an anonymous string pointer. Thus:

string s;
string* _s = &s;
myfunc(_s);

should compile just fine.

However, this is only useful if you intend to modify the pointer you pass to the function. If you intend to modify the string itself you should use a reference to the string as Sake suggested. With that in mind it should be more obvious why the compiler complains about you original code. In your code the pointer is created 'on the fly', modifying that pointer would have no consequence and that is not what is intended. The idea of a reference (vs. a pointer) is that a reference always points to an actual object.


The problem is that you're trying to bind a temporary to the reference, which C++ doesn't allow unless the reference is const.

So you can do one of either the following:

void myfunc(string*& val)
{
    // Do stuff to the string pointer
}


void myfunc2(string* const& val)
{
    // Do stuff to the string pointer
}

int main()
// sometime later 
{
    // ...
    string s;
    string* ps = &s;

    myfunc( ps);   // OK because ps is not a temporary
    myfunc2( &s);  // OK because the parameter is a const&
    // ...

    return 0;
}

Change it to:

  std::string s;
  std::string* pS = &s;
  myfunc(pS);

EDIT:

This is called ref-to-pointer and you cannot pass temporary address as a reference to function. ( unless it is const reference).

Though, I have shown std::string* pS = &s; (pointer to a local variable), its typical usage would be : when you want the callee to change the pointer itself, not the object to which it points. For example, a function that allocates memory and assigns the address of the memory block it allocated to its argument must take a reference to a pointer, or a pointer to pointer:

void myfunc(string*& val)
{
//val is valid even after function call
   val = new std::string("Test");

}

Try:

void myfunc(string& val)
{
    // Do stuff to the string pointer
}

// sometime later 
{
    // ...
    string s;
    myfunc(s);
    // ...
}

or

void myfunc(string* val)
{
    // Do stuff to the string pointer
}

// sometime later 
{
    // ...
    string s;
    myfunc(&s);
    // ...
}