Passing parameters stored in a list to expression

Question

How can I pass values to a given expression with several variables? The values for these variables are placed in a list that needs to be passed into the expression.

Answer 1

A couple other ways...

1. Use rule replacement

   f /. Thread[{a,b} -> l]

   (where Thread[{a,b} -> l] will evaluate into {a->1, b->2})

2. Use a pure function

   Function[{a,b}, Evaluate[f]] @@ l

   (where @@ is a form of Apply[] and Evaluate[f] is used to turn the function into Function[{a,b}, a^2+b^2])

Answer 2

Your revised question is straightforward, simply

f @@ {a,b,c,...} == f[a,b,c,...]

where @@ is shorthand for Apply. Internally, {a,b,c} is List[a,b,c] (which you can see by using FullForm on any expression), and Apply just replaces the Head, List, with a new Head, f, changing the function. The operation of Apply is not limited to lists, in general

f @@ g[a,b] == f[a,b]

Also, look at Sequence which does

f[Sequence[a,b]] == f[a,b]

So, we could do this instead

f[ Sequence @@ {a,b}] == f[a,b]

which while pedantic seeming can be very useful.

Edit: Apply has an optional 2^nd argument that specifies a level, i.e.

Apply[f, {{a,b},{c,d}}, {1}] == {f[a,b], f[c,d]}

Note: the shorthand for Apply[fcn, expr,{1}] is @@@, as discussed here, but to specify any other level description you need to use the full function form.