Passing **kwargs received in a wrapper-function definition, to arguments of an enclosed (i.e. wrapped) function call

Question

Oh dear, I hope I got the title right. :)

How can one pass the **kwargs supplied to a wrapper-function definition, to another (enclosed) function call that it wraps. For example:

def wrapped_func(**kwargs):
   # Do some preparation stuff here.
   func('/path/to/file.csv', comma_separated_key=value_injected_here)
   # Do some other stuff.

So for example, this call:

wrapped_func(error_bad_lines=True, sep=':', skip_footer=0, ...)

Should result in this:

func('/path/to/file.csv', error_bad_lines=True, sep=':', skip_footer=0, ...)

I've tinkered with a variety of approaches over the past couple of hours, but each exposed type-preservation vulnerabilities (for the values). I've not used this particular wrapper pattern before, and was wondering if the community could give some help. Thank you in advance.

Answer 1

**kwargs is a dict, meaning you can use the double splat (**) to unpack it as a list of keyword arguments. So your wrapper function could be like this:

def wrapped_func(**kwargs):
   # Do some preparation stuff here.
   func('/path/to/file.csv', **kwargs)
   # Do some other stuff.

Answer 2

Why not simply merge the kwargs:

def func(*args, **kwargs):
    print args
    print kwargs


def wrapped_func(**kwargs):
    # Do some preparation stuff here.
    func('/path/to/file.csv', **dict(comma_separated_key='value_injected_here', **kwargs))
    # Do some other stuff.


wrapped_func(error_bad_lines=True, sep=':', skip_footer=0)

# Outputs:
('/path/to/file.csv',)
{'skip_footer': 0, 'error_bad_lines': True, 'comma_separated_key': 'value_injected_here', 'sep': ':'}