I need to pass file as argument to the celery task, but the passed file somehow got there closed. It happens just in case I'm executing the task asynchronous way. Is this an expected behavior?
views:
from engine.tasks import s3_upload_handler
def myfunc():
f = open('/app/uploads/pic.jpg', 'rb')
s3_file_handler.apply_async(kwargs={"uploaded_file" : f,"file_name" : "test.jpg"})
tasks:
def s3_upload_handler(uploaded_file,file_name):
...
#some code for uploading to s3
traceback:
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/celery/app/trace.py", line 240, in trace_task
R = retval = fun(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/celery/app/trace.py", line 437, in __protected_call__
return self.run(*args, **kwargs)
File "/app/photohosting/engine/tasks.py", line 34, in s3_upload_handler
key.set_contents_from_file(uploaded_file)
File "/usr/local/lib/python2.7/dist-packages/boto/s3/key.py", line 1217, in set_contents_from_file
spos = fp.tell()
ValueError: I/O operation on closed file
flower logs:
kwargs {
'file_name': 'test.jpg',
'uploaded_file': <closed file '<uninitialized file>',
mode '<uninitialized file>' at 0x7f6ab9e75e40>
}
Yes, of course, the file would get there closed. Asynchronous celery tasks run in a completely separate process (moreover, they can even run on a different machine) and there is no way to pass an open file to it.
You should close the file in the process from where you call the task, and then pass its name and maybe position in file (if you need it) to the task and then reopen it in the task.
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