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passing ‘const this argument discards qualifiers [-fpermissive]

Tags:

gcc

g++

I have a class Cache which has a function write specified as

bool write(const MemoryAccess &memory_access, CacheLine &cl);

I am calling this function like this.

const Cache *this_cache;
c = (a==b)?my_cache:not_cache;
c->write(memory_access,cl);

The above line is giving me following error

"passing ‘const Cache’ as ‘this’ argument of ‘bool Cache::write(const MemoryAccess&, CacheLine&)’ discards qualifiers [-fpermissive]."

the this argument is compiler specific which helps in code-mangling and breaking local namespace variable priority. But such a variable is not being passed here.

like image 902
prathmesh.kallurkar Avatar asked May 26 '12 11:05

prathmesh.kallurkar


2 Answers

Since c is of type const Cache *, you can only call const member functions on it.

You have two options:

(1) remove const from the declaration of c;

(2) change Cache::write() like so:

 bool write(const MemoryAccess &memory_access, CacheLine &cl) const;

(Note the added const at the end.)

like image 59
NPE Avatar answered Nov 03 '22 01:11

NPE


When you call a method via a pointer to an object, this object is implicitly passed to the method as this pointer. c probably has type const Cache*. Since method write is not declared as const, it has non-const this pointer accessible from its body requiring const qualifier of c to be discarded.

like image 20
Alex Bakulin Avatar answered Nov 03 '22 01:11

Alex Bakulin