Passing C array as char* function parameter

Question

I've got some code I'm mantaining with the following variable declaration:

char tmpry[40];

It's being used with this function:

char *SomeFunction(char *tmpryP) {
   // Do stuff.
}

The function call is:

SomeFunction(&tmpry[0]);

I'm pretty damn sure that's just the same as:

SomeFunction(tmpry);

I've even checked that the char* pointer in SomeFunction ends up pointing to the same memory location as the array in both cases.

My question is a sanity check as to whether the two function calls are identical (and therefore the original programmer was just being nasty)?

Answer 1

they are exactly the same.

someArray[i]

means exactly

*(someArray + i)

where someArray in the second case is a pointer to the memory location. Similarly,

&someArray[i]

means exactly

(someArray + i)

In both these cases the terms are pointers to memory locations.

Answer 2

The two are equivalent and I think SomeFunction(tmpry); is more readable.