Passing arguments to model methods in Django templates

Question

I'm trying to get all customers from a specified business, but there is a class method in Customer model to get some information based on the same Business... Let me explain this with code...

class Business(models.Model):     ...     customers = models.ManyToManyField(Customer, blank=True, null=True)  class Customer(models.Model):     ...     def get_something(self, obj_business)         ... 

Ok now in my views I get all customers from a specified business like this:

obj_customers = obj_business.customers.all() 

Then I try to print this in my template:

{% for obj_customer in obj_customers %}     {{ obj_customer.get_something ....... }} 

But yes, there is not a way to pass arguments... I would like to know if there is something that I'm missing...

I wonder if there is another solution instead creating a template tag... because it is a ManyToManyField, if customers field had been just ForeignKey, no need to pass an argument to that method...

Answer 1

You can create a simple template tag to call any method with any arguments:

from django import template  register = template.Library()  @register.simple_tag def call_method(obj, method_name, *args):     method = getattr(obj, method_name)     return method(*args) 

And then in your template:

{% call_method obj_customer 'get_something' obj_business %} 

But, of course, crating of a specialized template tag is more safe :-)

@register.simple_tag def get_something(customer, business):     return customer.get_something(business) 

Template:

{% get_something obj_customer obj_business %} 

Answer 2

You cannot pass arguments to functions in Django templates.

Instead you can write your own template tag.

Here are some examples:

https://github.com/miohtama/LibertyMusicStore/blob/master/tatianastore/templatetags/content.py