I am having difficulty passing an array as an argument into int main()
with default values.
For example:
int main(int a){}
works wonderfully. As does
int main(int a = 1){}
Passing int main()
an array also works wonderfully:
int main(int a[3])
However, combining these two concepts seems break:
int main(int a[1] = {0,1})
After a significant amount of googleing, I haven't found a solution.
please help me SO, you're my only hope!
The purpose of this, in short, is to make my code as little lines as possible, for a challenge my professor recently issued (not for points -- just for learning). The assignment is to create a recursive "12-days-of-chirstmas" program
This is my current program
#include <iostream>
#include <string>
void p(std::string v){std::cout<<v;}
std::string v[13] = {"A Partridge in a Pear Tree.\n\n","2 Turtle Doves\n","3 French Hens\n","4 Colly Birds\n","5 Gold Rings\n","6 Geese-a-Laying\n","7 Swans-a-Swimming\n","8 Maids-a-Milking\n","9 Ladies Dancing\n","10 Lords-a-Leaping\n","11 Pipers Piping\n","12 Drummers Drumming\n",""};
int main(){
switch(v[12].length()){
case 12:system("pause"); return 0;
case 11:p(v[11]);
case 10:p(v[10]);
case 9: p(v[9]);
case 8: p(v[8]);
case 7: p(v[7]);
case 6: p(v[6]);
case 5: p(v[5]);
case 4: p(v[4]);
case 3: p(v[3]);
case 2: p(v[2]);
case 1: p(v[1]);
case 0: p(v[0]);
}v[12] += "0";
main();
}
I would like to pass in the array of verses as an argument to main instead of declaring it above the function. I know, not the most memory/stack conscious. But it would eliminate a line :)
This link explains it best:
In C++ it is not possible to pass a complete block of memory by value as a parameter to a function, but we are allowed to pass its address.
That's why you can declare a function with
void foo (int bar[]);
but you can't declare
void foo (int bar[] = {0 ,1});
It has nothing to do with main()
.
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