Passing all arguments of a function to another function

Question

I want to pass all the arguments passed to a function(func1) as arguments to another function(func2) inside func1 This can be done with *args, *kwargs in the called func1 and passing them down to func2, but is there another way?

Originally

def func1(*args, **kwargs):     func2(*args, **kwargs) 

but if my func1 signature is

def func1(a=1, b=2, c=3): 

how do I send them all to func2, without using

def func1(a=1, b=2, c=3):     func2(a, b, c) 

Is there a way as in javascript callee.arguments?

Answer 1

Explicit is better than implicit but if you really don't want to type a few characters:

def func1(a=1, b=2, c=3):     func2(**locals()) 

locals() are all local variables, so you can't set any extra vars before calling func2 or they will get passed too.