Passing a Vec into a function by reference

Question

I'm having some trouble passing a Vec<u64> into a function without moving it. I have a function find_factors(mut n: u64, mut fctrs: Vec<u64>) and I am currently calling from main like so:

fn main() {     let mut primeFactors: Vec<u64> = Vec::new();     find_factors(1134 as u64, primeFactors); } 

I'm forced right now to loop through and print out my vector in the find_factors function because I'm not sure how to pass the Vec<u64> by reference instead of moving it. How could I accomplish this? Example of what I want to do:

fn main() {     let mut primeFactors: Vec<u64> = Vec::new();     find_factors(1134 as u64, primeFactors);      //for ....         //print vector in main! } 

Answer 1

If you don't need to add or remove elements from the vector, use slice (&[T]) or mutable slice (&mut [T]):

fn find_factors(n: u64, prime_factors: &mut [u64]) { ... }  let mut prime_factors: Vec<u64> = Vec::new(); find_factors(1134 as u64, prime_factors.as_mut_slice()); 

Immutable slices allow you to read elements or create subslices; mutable slices additionally allow to modify elements. But slices cannot grow - they are just a view into some vector.

It looks like you need to append new elements to the vector. You won't be able to do it using slice, as I said; you need to pass the vector itself using mutable reference:

fn find_factors(n: u64, prime_factors: &mut Vec<u64>) {     // here you can call e.g. prime_factors.push(...) }  let mut prime_factors: Vec<u64> = Vec::new(); find_factors(1134 as u64, &mut prime_factors);