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If compiler is not C99 compatible, then we can use one of the following methods to pass a variable sized 2D array. In this method, we must typecast the 2D array when passing to function.
To pass an entire array to a function, only the name of the array is passed as an argument. result = calculateSum(num); However, notice the use of [] in the function definition. This informs the compiler that you are passing a one-dimensional array to the function.
matrix = variable(input1, input2); where 'matrix' is the output and 'variable' is the function name. 'input1' and 'input2' are also matrices of order 32x32.
I have an issue passing a matrix to a function in C. There is the function I want to create:
void ins (int *matrix, int row, int column);
but I noticed that in contrast to the vectors, matrix give me an error. How can I pass my matrix to a function so?
EDIT --> there is the code:
// Matrix
#include <stdio.h>
#define SIZE 100
void ins (int *matrix, int row, int column);
void print (int *matrix, int row, int column);
int main ()
{
int mat[SIZE][SIZE];
int row, col;
printf("Input rows: ");
scanf ("%d", &row);
printf("Input columns: ");
scanf ("%d", &col);
printf ("Input data: \n");
ins(mat, row, col);
printf ("You entered: ");
print(mat, row, col);
return 0;
}
void ins (int *matrix, int row, int column);
{
int i, j;
for (i = 0; i < row; i++)
{
for (j = 0; j < column; j++)
{
printf ("Row %d column %d: ", i+1, j+1);
scanf ("%d", &matrix[i][j]);
}
}
}
void print (int *matrix, int row, int column)
{
int i;
int j;
for(i=0; i<row; i++)
{
for(j=0; j<column; j++)
{
printf("%d ", matrix[i][j]);
}
printf("\n");
}
}
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