Passing a List into a method, modify the list within the method without affecting 'original'

Question

Sorry if the subject seems vague, I tried summing it up as best I can without knowing the exact terminology of what I'm trying to achieve.

Essentially I have a list and then I call a method

public List<int> myList;

void Start () {
    myList = new List<int>();
    myList.Add (1);
    myList.Add (2);

    doSomething(myList);

    foreach (int i in myList){
        print (i);
    }
}

In my method I'd like to do this (for example)

public void doSomething (List<int> myPassedList) 
{

    int A = 5;
    myPassList.Add (A);
    //... And then some other cool code with this modified list
}

However, I dont want the original list changed, I want it exactly as it was. Essentially when I pass the list into the method I'd like a duplicate of the list, which is then made new each time the method is called.

I want to see the console print '1' then '2'

but it will print '1', '2' and '5'

Hopefully this all makes sense! Thanks very much in advance for any help

Jim

Answer 1

List is a reference type so when you pass myPassedList as an argument to doSomething you are modifying the original list.

You have two options, either call ToList() or create a new list, as an example:

public void doSomething (List<int> myPassedList) 
{
    List<int> newList = myPassedList.ToList();
    int A = 5;
    newList.Add(A);
    //... And then some other cool code with this modified list
}

The original list myList will then only return 1 and 2.

Answer 2

If you write a method that works with a list but will not modify that list, then you should document this by code with

public void doSomething ( IEnumerable<int> myPassedValues ) 
{
    List<int> newList = myPassedValues.ToList();
    int A = 5;
    newList.Add(A);
    //... And then some other cool code with this modified list
}

Now you and all others will know, just by reading the declaration that the passed list will not be modified in this method.