passing a hex number to a function

Question

gcc 4.4.2 c89

I have these defines in our API header file.

/* Reason for releasing call */
#define UNASSIGNED_NUMBER      0x01  /* Number unassigned / unallocated */
#define NORMAL_CLEARING        0x10  /* Call dropped under normal conditions*/
#define CHANNEL_UNACCEPTABLE   0x06
#define USER_BUSY              0x11  /* End user is busy */
.
.
.

However, I want to pass one to a function but I am not sure of the type. I could pass as just an integer value? The release_call function takes one of these as its parameter. However, I am not sure as the defines are defined as hex notation.

drop_and_release_call(23, 6); /* Dropping call for CHANNEL_UNACCEPTABLE */


uint32_t drop_and_release_call(uint32_t port_num, uint32_t reason)
{
    release_call(port_num, reason);
}

Many thanks for any suggestions,

Answer 1

0x06 and 6 (and CHANNEL_UNACCEPTABLE) are equivalent. So is 0x11 and 17 (and USER_BUSY). There is no distinction of hexadecimal or decimal to the computer.

(You should write drop_and_release_call(23, CHANNEL_UNACCEPTABLE) for clarity.)

Answer 2

Yes, it's just an integer.

The hexadecimal aspect of it is only important when it's displayed for us to read.