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Pass variable to PhpUnit

Tags:

php

phpunit

I developed a set of test cases using phpunit used for testing both development site and the production site. The only difference is the domain name. How can I pass the domain from command line to phpunit test cases so that I do not need to modify every file?

like image 835
cuteCAT Avatar asked Dec 13 '11 15:12

cuteCAT


2 Answers

In your phpunit-bootstrap.php you can do something like this:

$site = getenv('DOMAIN');

and use

<php>
  <env name="DOMAIN" value="http://production.com"/>
</php>

in your phpunit.xml file as shown in the documentation.

The downside of this approach is that you need to have two different xml files.


Other options are using a custom wrapper script around phpunit like @DavidHarkness showed which tends to work out well

or, if you don't want to run those tests in an automated way (or use both approaches) to do something like:

$site = getenv('DOMAIN');
if(!$site) {
    echo "Enter Domain: ";
    $site = fgets(STDIN);
}

and have the runner check the environment and if nothing is there ask you for the domain.


Env or define or anything else

The same goes for pretty much every way that php can take in input from the outside world.

<php>
  <define name="DOMAIN" value="http://production.com"/>
</php>

also works in case you are using a constant anyways, for example.

like image 153
edorian Avatar answered Oct 19 '22 09:10

edorian


You could set an environment variable before running the tests. To make this easier on yourself, create a simple script to export the variable and run the tests.

#!/bin/bash

USAGE="Usage: $0 <domain> [file-or-directory]"

if [ "$#" == "0" ]; then
    echo "$USAGE"
    exit 1
fi

export TEST_DOMAIN=$1
shift
phpunit $*

In your base test case you can access this value using getenv:

$domain = getenv('TEST_DOMAIN');
like image 27
David Harkness Avatar answered Oct 19 '22 10:10

David Harkness