I would like to pass values from C program to Assembly using the linked assembly method instead of inline assembly method in C. Below is the Assembly program(GCD) which is am working on.
;gcdasm.nasm
bits 64
section .text
global gcdasm
gcdasm:
push rbp
mov rbp, rsp
mov rax, [rbp+4] ;load rax with x
mov rbx, [rbp+8] ;load rbx with y
top:
cmp rax, rbx ;x(rax) has to be larger than y(rbx)
je exit ;if x=y then exit and return value y
jb xchange ;if x<y then swap x and y
modulo:
cqo ;RDX:RAX sign extend
div rbx ;div rdx:rax with rbx
cmp rdx, 0 ;check remider if its 0
je exit ;if reminder is 0 then exit return return y
mov rax, rdx ;reminder rdx as next dividend
jmp modulo ;loop
xchange:
xchg rax, rbx ;swap x and y
jmp modulo
exit:
mov rax, rbx ;Return c program with the divisor y
mov rsp, rbp
pop rbp
ret
And this is the C program from with I am trying to pass the values to assembly program
//gcd.c
#include<stdio.h>
extern int gcdasm(int x, int y);
int main(void){
int x=0;
int y=0;
int result=0;
x = 46;
y = 90;
printf("%d and %d have a gcd of %d\n", x,y,gcdasm(x,y));
x = 55;
y = 66;
printf("%d and %d have a gcd of %d\n", x,y,gcdasm(x,y));
return 0;
}
When I compile using the below method and run it. I get either error Floating point exception
or an empty prompt waiting for input
$ nasm -felf64 gcdasm.nasm -o gcdasm.o
$ gcc gcdasm.o gcd.c -o gcd
$ ./gcd
Floating point exception
$ ./gcd
I am unable to figure out the error. Kindly help me out. Thank you.
To pass parameters to a subroutine, the calling program pushes them on the stack in the reverse order so that the last parameter to pass is the first one pushed, and the first parameter to pass is the last one pushed. This way the first parameter is on top of the stack and the last one is at the bottom of the stack.
We can write assembly program code inside c language program. In such case, all the assembly code must be placed inside asm{} block. Let's see a simple assembly program code to add two numbers in c program.
For 64-bit x86 Windows programs the arguments are passed in registers rcx , rdx , r8 and r9 . And for 64-bit x86 Linux programs the registers rdi , rsi , rcx , rdx , r8 and r9 are used.
gcdasm()
The two int
arguments are passed through registers, not the stack. The first and second arguments are passed in the lower-half of rdi
and rsi
(i.e.: edi
and esi
), respectively. So, by sign extending edi
and esi
into rax
and rbx
respectively, you load the passed arguments into those registers:
movsx rax, edi ;load rax with x
movsx rbx, esi ;load rbx with y
However, note that rbx
is not a scratch register, therefore the callee needs to save it before modifying it and then restore it back before leaving the gcdasm
function.
You can simply replace rbx
by rcx
(which isn't a callee-saved register) everywhere in your code. You don't need rbp
at all, so you can remove all the instructions where rbp
appears.
There is also a problem with the logic of the program with:
mov rax, rdx ;reminder rdx as next dividend
Instead of this, the divisor (rcx
) should become the dividend (rax
) and the remainder (rdx
) should become the divisor (rcx
), that is:
mov rax, rcx
mov rcx, rdx
When dividing signed values, you have to use the idiv
instruction, not div
.
There are also some reasons regarding performance and code size to use test rdx, rdx
instead of cmp rdx, 0
for comparing rdx
against zero.
With all that above in mind:
;gcdasm.nasm
bits 64
section .text
global gcdasm
gcdasm:
movsx rax, edi ;load rax with x
movsx rcx, esi ;load rcx with y
top:
cmp rax, rcx ;x(rax) has to be larger than y(rcx)
je exit ;if x=y then exit and return value y
jb xchange ;if x<y then swap x and y
modulo:
cqo ;sign extend RDX:RAX
idiv rcx ;rdx:rax/rcx (signed values)
test rdx, rdx ;check whether remainder is zero
je exit ;if reminder is 0 then exit return y
mov rax, rcx ;divisor becomes dividend
mov rcx, rdx ;remainder becomes divisor
jmp modulo ;loop
xchange:
xchg rax, rcx ;swap x and y
jmp modulo
exit:
mov rax, rcx ;Return c program with the divisor y
ret
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