Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Pass a model to a partial view?

this is my partial:

@model RazorSharpBlog.Models.MarkdownTextAreaModel

<div class="wmd-panel">
    <div id="[email protected]"></div>
    @Html.TextAreaFor(m => m.Name, new { @id = "wmd-input-" + @Model.Name, @class = "wmd-input" })
</div>
<div class="wmd-panel-separator"></div>
<div id="[email protected]" class="wmd-panel wmd-preview"></div>

<div class="wmd-panel-separator"></div>

I'm trying to include it like this in my View:

@using (Html.BeginForm())
{
    @Html.LabelFor(m => m.Title)
    @Html.TextBoxFor(m => m.Title)

    @Html.Partial("MarkdownTextArea", new { Name = "content" })

    <input type="submit" value="Post" />
}

these are the model classes:

public class MarkdownTextAreaModel
{
    [Required]
    public string Name { get; set; }
}

public class BlogContentModel 
{
    [Required]
    [Display(Name = "Post Title")]
    public string Title { get; set; }

    [Required]
    [DataType(DataType.MultilineText)]
    [Display(Name = "Post Content")]
    public string Content { get; set; }
}

What am I doing wrong, how should I do this in order to make my partial reusable?

like image 297
bevacqua Avatar asked Dec 09 '22 06:12

bevacqua


1 Answers

Your partial expects an instance of the MarkdownTextAreaModel class. So do so, instead of passing an anonymous object which would throw anyways:

@Html.Partial("MarkdownTextArea", new MarkdownTextAreaModel { Name = "content" })

Now this being said a far better solution would be to adapt your view model, so that it contains a reference to MarkdownTextAreaModel and use editor templates instead of partials in your views, just like so:

public class BlogContentModel 
{
    [Required]
    [Display(Name = "Post Title")]
    public string Title { get; set; }

    [Required]
    [DataType(DataType.MultilineText)]
    [Display(Name = "Post Content")]
    public string Content { get; set; }

    public MarkdownTextAreaModel MarkDown { get; set; }
}

then of course readapt the controller serving this view so that it populates the MarkDown of your view model:

public ActionResult Foo()
{
    BlogContentModel model = .... fetch this model from somewhere (a repository?)
    model.MarkDown = new MarkdownTextAreaModel
    {
        Name = "contect"
    };
    return View(model);
}

and then inside your main view simply:

@using (Html.BeginForm())
{
    @Html.LabelFor(m => m.Title)
    @Html.TextBoxFor(m => m.Title)

    @Html.EditorFor(x => x.MarkDown)

    <input type="submit" value="Post" />
}

and then in order to follow standard conventions move your partial to ~/Views/YourControllerName/EditorTemplates/MarkdownTextAreaModel.cshtml and now everything will magically come into place as it should.

like image 72
Darin Dimitrov Avatar answered Dec 22 '22 01:12

Darin Dimitrov