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I need to parse an RFC 2822 string representation of a date in Java. An example string is here:
Sat, 13 Mar 2010 11:29:05 -0800
It looks pretty nasty so I wanted to make sure I was doing everything right and would run into weird problems later with the date being interpreted wrong either through AM-PM/Military time problems, UTC time problems, problems I don't anticipate, etc...
Thanks!
876
For parsing a String to Date we need an instance of the SimpleDateFormat class and a string pattern as input for the constructor of the class. String pattern = "MM-dd-yyyy"; SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern); Date date = simpleDateFormat. parse("12-01-2018"); System.
DateValidator validator = new DateValidatorUsingDateFormat("MM/dd/yyyy"); assertTrue(validator. isValid("02/28/2019")); assertFalse(validator. isValid("02/30/2019"));
DateFormat is an abstract class for date/time formatting subclasses which formats and parses dates or time in a language-independent manner. The date/time formatting subclass, such as SimpleDateFormat , allows for formatting (i.e., date -> text), parsing (text -> date), and normalization.
This is quick code that does what you ask (using SimpleDateFormat)
String rfcDate = "Sat, 13 Mar 2010 11:29:05 -0800";
String pattern = "EEE, dd MMM yyyy HH:mm:ss Z";
SimpleDateFormat format = new SimpleDateFormat(pattern);
Date javaDate = format.parse(rfcDate);
//Done.
PS. I've not dealt with exceptions and concurrency here (as SimpleDateFormat is not synchronized when parsing date).
79
If your application is using another language than English, you may want to force the locale for the date parsing/formatting by using an alternate SimpleDateFormat constructor:
String pattern = "EEE, dd MMM yyyy HH:mm:ss Z";
SimpleDateFormat format = new SimpleDateFormat(pattern, Locale.ENGLISH);
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