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Parsing JSON using the new Swift 3 and Alamofire

I'm using Alamofire as HTTP library, since the update to Swift 3, how do you parse JSON based on the example below?

Alamofire.request("https://httpbin.org/get").responseJSON { response in
    debugPrint(response)

    if let json = response.result.value {
        print("JSON: \(json)")
    }
}

respone.result.value is of Any object, and is very new and confusing.

like image 342
Lawrence Gimenez Avatar asked Sep 13 '16 11:09

Lawrence Gimenez


2 Answers

As you can see in Alamofire tests you should cast response.result.value to [String:Any]:

if let json = response.result.value as? [String: Any] {
  // ...
}
like image 131
mixel Avatar answered Nov 16 '22 02:11

mixel


Updated for swift 3 :

if your response is like below,

[
    {
        "uId": 1156,
        "firstName": "Kunal",
        "lastName": "jadhav",
        "email": "[email protected]",
        "mobile": "7612345631",
        "subuserid": 4,
        "balance": 0
    }
]

**if you want to parsing the above JSON response used below simple lines of code: **

    Alamofire.request(yourURLString, method: .get, encoding: JSONEncoding.default)
        .responseJSON { response in
            debugPrint(response)

            if let data = response.result.value{

                if  (data as? [[String : AnyObject]]) != nil{

                    if let dictionaryArray = data as? Array<Dictionary<String, AnyObject?>> {
                        if dictionaryArray.count > 0 {

                            for i in 0..<dictionaryArray.count{

                                let Object = dictionaryArray[i]
                                if let email = Object["email"] as? String{
                                    print("Email: \(email)")
                                }
                                if let uId = Object["uId"] as? Int{
                                    print("User Id: \(uId)")
                                }
                                // like that you can do for remaining...
                            }
                        }
                    }
                }
            }
            else {
                let error = (response.result.value  as? [[String : AnyObject]])
                print(error as Any)
            }
    }
like image 45
Kiran Jadhav Avatar answered Nov 16 '22 03:11

Kiran Jadhav