I have a fixed-length byte array that is 1250 bytes long. It may contain the following types of data:
Object A which consists of 5 bytes. The first byte contains the letter "A" and the next four bytes store an integer from 1 - 100000.
Object B which consists of 2 bytes. The first byte contains the letter "B" and the next byte contains an integer from 1 - 100.
Object C which consists of 50 bytes. All 50 bytes are used to store an ASCII-encoded string which will only consist of numbers and the following characters: - + ( and )
I don't know how many of each object type are in the byte array but I do know that they are grouped together (Object B, Object B, Object A, Object A, Object A, Object C, etc.). Most of the time when I parse a byte array, the array contains data of one type (all items are Object A, for example) so I know exactly how many bytes each item is comprised of and I just loop through the array processing the bytes. In this case, I have three different types of data that are all different lengths. I was thinking that I would need to do something like this:
int offset = 0;
while (offset <= 1250)
{
string objectHeader = Encoding.ASCII.GetString(byteArray, offset, 1);
if (objectHeader.Equals("A"))
{
// read 4 more bytes and then convert into int value (1 - 100000)
index += 5;
}
else if (objectHeader.Equals("B"))
{
// read 1 more byte and then convert into int value (1 - 100)
index += 2;
}
else
{
// read 49 more bytes and then convert into a string
index += 50;
}
}
Is there a better way of doing this?
The bytearray() method returns a bytearray object, which is an array of bytes. It returns a mutable series of integers between 0 and 256. The source parameter of the ByteArray is used to initialize the array.
A byte array is simply an area of memory containing a group of contiguous (side by side) bytes, such that it makes sense to talk about them in order: the first byte, the second byte etc..
String also has a constructor where we can provide byte array and Charset as an argument. So below code can also be used to convert byte array to String in Java. String str = new String(byteArray, StandardCharsets. UTF_8);
A byte is 8 bits of binary data so do byte array is an array of bytes used to store the collection of binary data.
Well, there seems to be a little confusion with offset and index, maybe you should be using a for-loop:
for(int index = 0; index < 1250; index++)
{
switch(byteArray[index])
{
case (byte)'A':
index++;
int value = BitConverter.ToInt32(byteArray, index);
index += 4;
break;
case (byte)'B':
index++;
// Read the next byte as integer.
int value = (int)byteArray[index];
index++;
break;
case (byte)'C': // string.
index++;
// Read the next 49 bytes as an string.
StringBuilder value = new StringBuilder(49);
for(int i = index; i < index + 49; index++)
{
if (byteArray[i] == 0) break;
value.Append(Converter.ToChar(byteArray[i]));
}
index+= 49;
break;
case 0: // Finished.
index = 1250;
break;
default:
throw new InvalidArgumentException("Invalid byte array format");
}
}
How do you see if there is no more objects? In my example I suggest it ends with a '\0'.
Good luck with your quest.
int offset = 0;
while (offset <= 1250)
{
switch (byteArray[offset])
{
case (byte)'A':
//read other data ..
offset += 5;
break;
case (byte)'B':
//read other data ..
offset += 2;
break;
case (byte)'C':
//read other data ..
offset += 50;
break;
default:
//error
break;
}
}
Or another variant with binary reader:
var reader = new BinaryReader(new MemoryStream(byteArray), Encoding.ASCII);
while (reader.BaseStream.Position < reader.BaseStream.Length)
{
switch(reader.ReadChar())
{
case 'A':
{
var i = reader.ReadInt32();
return new TypeA(i);
}
break;
case 'B':
{
var i = reader.ReadByte();
return new TypeB(i);
}
break;
case 'C':
{
var chars = reader.ReadChars(49);
return new TypeC(new string(chars.TakeWhile(ch => ch != 0).ToArray()));
}
break;
}
}
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