I have this very long string in MSSQL which I require the I value.
I represents Invoice, A represents Amount, D represents Date
I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209
This is one of the scariest cases.
Each of these are invoice numbers which have relevant values which i will use to link to another transaction. I would really appreciate it if someone could explain the best manner to go about this without making a app if possible
String parsing is a common task for data analysts and data engineers working with raw data. With the growth of unstructured qualitative data, parsing strings efficiently has become increasingly important for fast analysis.
Simple SQL operations like LOAD, ALTER, INSERT, and UPDATE can turn parsing data from a chore into an efficient and mistake-free task.
The parsing stage involves separating the pieces of a SQL statement into a data structure that other routines can process. The database parses a statement when instructed by the application, which means that only the application, and not the database itself, can reduce the number of parses.
Use the SUBSTRING() function. The first argument is the string or the column name. The second argument is the index of the character at which the substring should begin. The third argument is the length of the substring.
declare @s varchar(max) = 'I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209'
declare @xml xml
select @xml = '<item><value>'+replace(replace(@s, ';','</value><value>'), '|','</value></item><item><value>')+'</value></item>'
select N.value('substring(value[1],3)', 'int') as Invoice,
N.value('substring(value[2],3)', 'money') as Amount,
N.value('substring(value[3],3)', 'date') as [Date]
from @xml.nodes('item') as T(N)
Result:
Invoice Amount Date
----------- --------------------- ----------
940 29,50 2009-09-01
941 62,54 2009-09-10
942 58,99 2009-10-05
954 93,45 2009-12-01
944 96,76 2009-11-01
946 52,50 2009-11-01
943 28,32 2009-11-01
945 52,50 2009-11-01
955 79,81 2009-12-01
950 25,20 2009-11-24
948 31,86 2009-11-10
949 28,32 2009-11-20
947 25,20 2009-11-09
951 242,54 2009-11-24
952 28,32 2009-11-29
956 38,94 2009-12-10
957 107,39 2009-12-15
958 32,55 2009-12-28
959 27,30 2009-12-28
960 24,79 2009-12-30
1117 28,32 2010-01-31
1115 272,58 2010-01-31
1116 159,60 2010-02-09
For SQL Server 2005 you need to use datetime instead of date
select N.value('substring(value[1],3)', 'int') as Invoice,
N.value('substring(value[2],3)', 'money') as Amount,
N.value('substring(value[3],3)', 'datetime') as [Date]
from @xml.nodes('item') as T(N)
To read from a table you need to do it like this.
declare @s varchar(max) = 'I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209'
declare @YourTable table(ID int, s varchar(max))
insert into @YourTable values
(1, @s),
(2, @s)
select Y.ID,
T.N.value('substring(value[1],3)', 'int') as Invoice,
T.N.value('substring(value[2],3)', 'money') as Amount,
T.N.value('substring(value[3],3)', 'date') as [Date]
from @YourTable as Y
cross apply (select cast('<item><value>'+replace(replace(Y.s, ';','</value><value>'), '|','</value></item><item><value>')+'</value></item>' as xml)) as X(XMLCol)
cross apply X.XMLCol.nodes('item') as T(N)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With