I have some large shapefiles with multiple millions of polygons that I need to dissolve. Depending upon the shapefile I need to either dissolve by group or just use st_union
for all. I have been using the st_par
function and it has been working great for most sf applications. Though when I use this function on st_union
it returns a list and I cannot figure out how to parallize the sf dissolve function st_union
.
Any suggestions would be most helpful! Here is a small code snippet to illustrate my point.
library(sf)
library(assertthat)
library(parallel)
us_shp <- "data/cb_2016_us_state_20m/cb_2016_us_state_20m.shp"
if (!file.exists(us_shp)) {
loc <- "https://www2.census.gov/geo/tiger/GENZ2016/shp/cb_2016_us_state_20m.zip"
dest <- paste0("data/cb_2016_us_state_20m", ".zip")
download.file(loc, dest)
unzip(dest, exdir = "data/cb_2016_us_state_20m")
unlink(dest)
assert_that(file.exists(us_shp))
}
usa <- st_read("data/cb_2016_us_state_20m/cb_2016_us_state_20m.shp", quiet= TRUE) %>%
filter(!(STUSPS %in% c("AK", "HI", "PR")))
test <- usa %>%
st_par(., st_union, n_cores = 2)
I think you can solve your specific problem with a small modification of the original st_par
function.
However this is just a quick and bold fix and this might broke the code for other uses of the function.
The author of the function could certainly provide a better fix...
library(parallel)
# Paralise any simple features analysis.
st_par <- function(sf_df, sf_func, n_cores, ...){
# Create a vector to split the data set up by.
split_vector <- rep(1:n_cores, each = nrow(sf_df) / n_cores, length.out = nrow(sf_df))
# Perform GIS analysis
split_results <- split(sf_df, split_vector) %>%
mclapply(function(x) sf_func(x), mc.cores = n_cores)
# Combine results back together. Method of combining depends on the output from the function.
if ( length(class(split_results[[1]]))>1 | class(split_results[[1]])[1] == 'list' ){
result <- do.call("c", split_results)
names(result) <- NULL
} else {
result <- do.call("rbind", split_results)
}
# Return result
return(result)
}
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