When I try to convert some columns in a pandas dataframe from '0' and '1' to 'TRUE' and 'FALSE', pandas automatically detects dtype as boolean. I want to keep dtype as string, with the strings 'TRUE' and 'FALSE'.
See code below:
booleanColumns = pandasDF.select_dtypes(include=[bool]).columns.values.tolist()
booleanDictionary = {'1': 'TRUE', '0': 'FALSE'}
pandasDF.to_string(columns = booleanColumns)
for column in booleanColumns:
pandasDF[column].map(booleanDictionary)
Unfortunately, python automatically converts dtype to boolean with the last operation. How can I prevent this?
Convert bool to string: str() You can convert True and False to strings 'True' and 'False' with str() .
You can multiply the return Boolean values (TRUE or FALSE) by 1, and then the TRUE will change to 1, and FALSE to 0.
Pandas DataFrame bool() MethodThe bool() method returns a boolean value, True or False, reflecting the value of the DataFrame. This method will only work if the DataFrame has only 1 value, and that value must be either True or False, otherwise the bool() method will return an error.
If need replace boolean
values True
and False
:
booleandf = pandasDF.select_dtypes(include=[bool])
booleanDictionary = {True: 'TRUE', False: 'FALSE'}
for column in booleandf:
pandasDF[column] = pandasDF[column].map(booleanDictionary)
Sample:
pandasDF = pd.DataFrame({'A':[True,False,True],
'B':[4,5,6],
'C':[False,True,False]})
print (pandasDF)
A B C
0 True 4 False
1 False 5 True
2 True 6 False
booleandf = pandasDF.select_dtypes(include=[bool])
booleanDictionary = {True: 'TRUE', False: 'FALSE'}
#loop by df is loop by columns, same as for column in booleandf.columns:
for column in booleandf:
pandasDF[column] = pandasDF[column].map(booleanDictionary)
print (pandasDF)
A B C
0 TRUE 4 FALSE
1 FALSE 5 TRUE
2 TRUE 6 FALSE
EDIT:
Simplier solution with replace
by dict
:
booleanDictionary = {True: 'TRUE', False: 'FALSE'}
pandasDF = pandasDF.replace(booleanDictionary)
print (pandasDF)
A B C
0 TRUE 4 FALSE
1 FALSE 5 TRUE
2 TRUE 6 FALSE
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