I'm trying to change a format of pd data frame column without changing the type of data.
Here is what I have: df = pd.DataFrame({'Age': [24.0, 32.0}])
I'd like to represent Age in 24 32
type or 24.00 32.00
and keep them as floats.
Here is what I can do:
df['Age'].map('{:,.2f}'.format)
But this line changes the type of data to object. I was also trying to apply: `
df = df.style.format({'Age': '{:,.2f}'.format})`
but there is something wrong in it. Please help to figure out the right way.
Your dataFrame itself a type float.
Dataframe:
>>> df
Age
0 24.0
1 32.0
Check DataFrame type:
>>> df.dtypes
Age float64
dtype: object
check dtype for DataFrame column type:
>>> df.Age
0 24.0
1 32.0
Name: Age, dtype: float64
OR even check like:
>>> df['Age'].dtype.kind
'f'
The way you are using to round up double digit zeros that's correct but converting them again to float will get them remain in single zero as being float.
>>> df['Age'].map('{:,.2f}'.format)
0 24.00
1 32.00
Name: Age, dtype: object
As you are interested keeping either mimic like int values 24, 32
or 24.00 & 32.00
, if you are only interested in the display of floats then you can do pd.set_option('display.float_format','{:.0f}'.format)
, which doesn't actually affect your data.
>>> pd.set_option('display.float_format','{:.0f}'.format)
>>> df
Age
0 24
1 32
>>> df.dtypes
Age float64
dtype: object
>>> pd.set_option('display.float_format','{:.2f}'.format)
>>> df
Age
0 24.00
1 32.00
>>> df.dtypes
Age float64
dtype: object
Set the display precision option:
>>> pd.set_option('precision', 0)
>>> df
Age
0 24
1 32
>>> df.dtypes
Age float64
dtype: object
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