I have a pandas DataFrame with a DateTimeIndex
:
A B
2016-04-25 18:50:06 440.967796 201.049600
2016-04-25 18:50:13 441.054995 200.767034
2016-04-25 18:50:20 441.142337 200.484475
...
2016-07-27 18:50:06 440.967796 201.049600
2016-07-27 18:50:13 441.054995 200.767034
2016-07-27 18:50:20 441.142337 200.484475
I would like to extract all the data of a given date yyyy-mm-dd
using a list of dates: ['2016-04-25','2016-04-28',...]
I tried the following:
df[df.index.isin(['2016-04-25', '2016-04-26'])]
Empty DataFrame
I would like to retrieve all the data (data of the whole day) of the dates given in this list
date attribute outputs an Index object containing the date values present in each of the entries of the DatetimeIndex object. Example #1: Use DatetimeIndex. date attribute to find the date part of the DatetimeIndex object.
Pandas has a built-in function called to_datetime()that converts date and time in string format to a DateTime object. As you can see, the 'date' column in the DataFrame is currently of a string-type object. Thus, to_datetime() converts the column to a series of the appropriate datetime64 dtype.
In order to select rows between two dates in pandas DataFrame, first, create a boolean mask using mask = (df['InsertedDates'] > start_date) & (df['InsertedDates'] <= end_date) to represent the start and end of the date range. Then you select the DataFrame that lies within the range using the DataFrame.
You need remove times first by this solutions:
df = df[df.index.normalize().isin(['2016-04-25', '2016-04-26'])]
df = df[df.index.floor('D').isin(['2016-04-25', '2016-04-26'])]
Another solution is compare DatetimeIndex.date
, but necessary use numpy.in1d
instead isin
:
df = df[np.in1d(df.index.date, pd.to_datetime(['2016-04-25', '2016-04-26']).date)]
Or compare strings created DatetimeIndex.strftime
:
df = df[np.in1d(df.index.strftime('%Y-%m-%d'), ['2016-04-25', '2016-04-26'])]
print (df)
A B
2016-04-25 18:50:06 440.967796 201.049600
2016-04-25 18:50:13 441.054995 200.767034
2016-04-25 18:50:20 441.142337 200.484475
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