overriding interface method

Question

For a interface such as

public interface something<T>
{
   public something<T> somemethod();
}

from what i understand the abstract method somemethod() needs to overridden with a method that returns an object implementing the interface. However, any attempts to do so have given me the "does not override the abstract method somemethod()" compiler error.

I've tried doing something like

public class someclass {
...
    public something<T> somemethod() { ... return new someclass(); }
...
or 
    public someclass somemethod() { ... return new someclass(); }
...
}

How exactly would i implement such a method?

Answer 1

You're missing the generic declaration in your implementing class. Here's an example:

public interface Something <T> {

    public Something<T> someMethod();

}

class SomethingImplementation <T> implements Something <T> {

    @Override
    public Something<T> someMethod() {
        return null;
    }

}

Answer 2

All of these should compile:

class test<T> implements something<T>{
    public something<T> somemethod(){
        return new test<T>();
    }
}

class test1<T> implements something<T>{
    public test1<T> somemethod(){
        return new test1<T>();
    }
}   

class test2 implements something<Integer>{
    public something<Integer> somemethod(){
        return new test2();
    }
}

class test3 implements something<Integer>{
    public test3 somemethod(){
        return new test3();
    }
}