Override the 'is' functionality

Question

I have a class so contains a exception, as so.

public class ExceptionWrapper {     public string TypeName { get; set; }     public string Message { get; set; }     public string InnerException { get; set; }     public string StackTrace { get; set; }      public ExceptionWrapper() { }      public ExceptionWrapper(Exception ex)     {         TypeName = String.Format("{0}.{1}", ex.GetType().Namespace, ex.GetType().Name);         Message = ex.Message;         InnerException = ex.InnerException != null ? ex.InnerException.Message : null;         StackTrace = ex.StackTrace;     }      public bool Is(Type t)     {         var fullName = String.Format("{0}.{1}", t.Namespace, t.Name);         return fullName == TypeName;     } } 

I want to override the 'is' action, So instead of doing so

if (ex.Is(typeof(Validator.ValidatorException)) == true) 

I will do so

if (ex is Validator.ValidatorException) 

Is it possible? How?

Answer 1

From Overloadable Operators, the following operators can be overloaded:

• Unary: +, -, !, ~, ++, --, true, false
• Binary: +, -, *, /, %, &, |, ^, <<, >>
• Comparison: ==, !=, <, >, <=, >=

And these operators cannot be overloaded:

• Logical: &&, ||
• Array Indexing: []
• Cast: (T)x
• Assignment: +=, -=, *=, /=, %=, &=, |=, ^=, <<=, >>=
• Others: =, ., ?:, ??, ->, =>, f(x), as, checked, unchecked, default, delegate, is, new, sizeof, typeof

Also, comparison operators need to be overloaded in pairs, if you overload one, you must overload the other:

• == and !=
• < and >
• <= and >=