Overload dereferencing operator (operator*())

Question

Here is my operator definition in my class :

T& operator*(){
        return this->element_; 
}

When I use it like that, it is called :

std::cout << n->operator*() << std::endl;

It doesn't, if I try :

std::cout << *n << std::endl;

Any Idea ?

Thanks in advance,

Jérémy

Answer 1

Looks like n is itself a pointer, so you need **n