I have a problem with rendering of Mesh
lines on a 3D surface produced by ContourPlot3D
in Mathematica 7.0.1:
p=ContourPlot3D[x^4+y^4+z^4-(x^2+y^2+z^2)^2+3(x^2+y^2+z^2)==3,
{x, -2,2}, {y, -2, 2}, {z,-2,2},
BoundaryStyle->Directive[Black,Thickness[.003]],
ContourStyle->Directive[Orange,Opacity[0.5],Specularity[White,300]],
PlotPoints->90,Ticks->None,
MeshStyle->Directive[GrayLevel[.7],Thickness[.001]],
Lighting->{{"Directional",RGBColor[1,1,1],
{ImageScaled@{1,0,1},ImageScaled@{0,0,0}}}}];
p=Graphics[Inset[p,{0,0},Center,{1,1}],
PlotRange->{{-.5,.5},{-.5,.5}},Frame->True]
Look closer on them:
Show[p, PlotRange -> {{-.16, -.05}, {0, .1}}]
You see that gray Mesh
lines are overlapped by surface-forming triangles in many places and even look dashed. Is there a way to avoid this?
John Fultz has answered my question in the official newsgroup. The solution for Mathematica 7 users (and probably for version 8 users who have a graphics card without support for DepthPeeling
rendering method) is to use an undocumented form of MeshStyle
option:
MeshStyle -> {{GrayLevel[.7], Tube[0.01]}}
For having Mesh
lines appear as flat objects one can use Glow
:
MeshStyle -> {{Glow[GrayLevel[.7]], Black, Tube[0.005]}}
Now mesh is rendered nicely:
p1 = ContourPlot3D[
x^4 + y^4 + z^4 - (x^2 + y^2 + z^2)^2 + 3 (x^2 + y^2 + z^2) ==
3, {x, -2, 2}, {y, -2, 2}, {z, -2, 2},
BoundaryStyle -> Directive[Black, Thickness[.003]],
ContourStyle ->
Directive[Orange, Opacity[0.5], Specularity[White, 300]],
Ticks -> None, PlotPoints -> 40,
MeshStyle -> {{Glow[GrayLevel[.7]], Black, Tube[0.005]}},
Lighting -> {{"Directional",
RGBColor[1, 1, 1], {ImageScaled@{1, 0, 1},
ImageScaled@{0, 0, 0}}}}];
p = Graphics[Inset[p1, {0, 0}, Center, {1, 1}],
PlotRange -> {{-.5, .5}, {-.5, .5}}, Frame -> True,
GridLines -> Automatic]
Show[p, PlotRange -> {{-.16, -.05}, {0, .1}}]
For what it's worth, I don't see this problem in M8.0.1 on Mac OS 10.7.1:
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