I am wondering if it is possible to dictate the order (i.e. :order => 'created_at DESC') within the view. I realize that logic in the view is not ideal but I seem to be having some problems locating where to affect this output.
For instance, here is my code:
<% @user.questions.each do |question| %>
<%= link_to_unless_current h (question.title), question %>
Created about <%= time_ago_in_words h(question.created_at) %> ago
Updated about <%= time_ago_in_words h(question.updated_at) %> ago
<%= link_to 'Edit', edit_question_path(question) %> |
<%= link_to 'Destroy', question, :confirm => 'Are you sure?', :method => :delete %>
<% end %>
In my QuestionsController I have the following index action but it is not affecting the output from the code above.
class QuestionsController < ApplicationController
def index
@questions = Question.all(:order => 'created_at DESC', :limit => 20)
respond_to do |format|
format.html # index.html.erb
format.xml { render :xml => @questions }
end
end
end
UPDATE: With respect to changing the @user.questions to @questions I get this error:
You have a nil object when you didn't expect it!
You might have expected an instance of Array.
The error occurred while evaluating nil.each
UPDATE 2: I guess I should mention that this code is in the questions show view. views/questions/show.html.erb.
You can use:
<% unless @questions.empty? %>
<% @questions.each do |question| %>
# ...
<% end %>
<% end %>
in your view and
@questions = Question.all(:order => 'created_at DESC', :limit => 20)
inside show
or index
method of QuestionsController
.
An easy way to do it is to use reverse_each
instead of each
:
<% @user.questions.reverse_each do |question| %>
You get your questions in the descending order, and don't touch anything in the controller.
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