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In an if statement with multiple conditionals, is the second conditional executed if the outcome of the first is clear?
example:
if(i>0 && array[i]==0){ } If I swap the conditionals a segfault may occur for negative values of i, but this way no segfault occurs. Can I be sure that this always works or do have have to use nested if statements?
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When you combine each one of them with an IF statement, they read like this: AND – =IF(AND(Something is True, Something else is True), Value if True, Value if False) OR – =IF(OR(Something is True, Something else is True), Value if True, Value if False) NOT – =IF(NOT(Something is True), Value if True, Value if False)
nested-if in C/C++ Nested if statements mean an if statement inside another if statement. Yes, both C and C++ allow us to nested if statements within if statements, i.e, we can place an if statement inside another if statement.
The if-else-if statement is used to execute one code from multiple conditions. It is also called a multipath decision statement.
Using either “&&” or “||” i.e. logical AND or logical OR operator or combination of can achieve 3 conditions in if statement JavaScript.
This type of evaluation is called short-circuiting. Once the result is 100% clear, it does not continue evaluating.
This is actually a common programming technique. For example, in C++ you will often see something like:
if (pX!=null && pX->predicate()) { bla bla bla } If you changed the order of the conditions, you could be invoking a method on a null pointer and crashing. A similar example in C would use the field of a struct when you have a pointer to that struct.
You could do something similar with or:
if(px==null || pX->isEmpty()} { bla bla bla } This is also one of the reasons that it is generally a good idea to avoid side effects in an if condition.
For example suppose you have:
if(x==4 && (++y>7) && z==9) If x is 4, then y will be incremented regardless of the value of z or y, but if x is not 4, it will not be incremented at all.
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