new T[7]
creates an array of 7 T
s. If we replace T
with int[5]
, we get new int[5][7]
which should create an array of 7 arrays of 5 integers. However, it creates an array of 5 arrays of 7 integers instead. Is there any good reason for this? Wouldn't it make more sense if it was the other way around?
Which of the following is the correct way to declare a multidimensional array in Java? Explanation: The syntax to declare multidimensional array in java is either int[][] arr; or int arr[][]; 5.
You must create each multidimensional ARRAY/VARRAY type you need for your applications using a CREATE TYPE (ARRAY form) request. When you create a new multidimensional ARRAY/VARRAY type, you must explicitly specify the lower and upper boundaries for each dimension, as well as the element data type of the array.
Data in multidimensional arrays are stored in row-major order. The general form of declaring N-dimensional arrays is: data_type array_name[size1][size2]....[sizeN];
You can create a multidimensional array by creating a 2-D matrix first, and then extending it. For example, first define a 3-by-3 matrix as the first page in a 3-D array. Now add a second page. To do this, assign another 3-by-3 matrix to the index value 2 in the third dimension.
I think of it as dimensions:
height width depth
int[5] [7] [8]
Or
rows cols
int[5] [7]
That's why it makes sense for it to be 5 arrays of 7 ints to me. There is a kind of natural order.
I think your example also makes sense and is very logical. So I guess it's just a matter of opinion :P
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