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ORDER BY the IN value list

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How do I sort by value in SQL?

The SQL ORDER BY Keyword The ORDER BY keyword is used to sort the result-set in ascending or descending order. The ORDER BY keyword sorts the records in ascending order by default. To sort the records in descending order, use the DESC keyword.

Can you group by and ORDER BY?

Using Group By and Order By Together When combining the Group By and Order By clauses, it is important to bear in mind that, in terms of placement within a SELECT statement: The GROUP BY clause is placed after the WHERE clause. The GROUP BY clause is placed before the ORDER BY clause.

What does ORDER BY 1 do in SQL?

it simply means sorting the view or table by 1st column of the query's result.


You can do it quite easily with (introduced in PostgreSQL 8.2) VALUES (), ().

Syntax will be like this:

select c.*
from comments c
join (
  values
    (1,1),
    (3,2),
    (2,3),
    (4,4)
) as x (id, ordering) on c.id = x.id
order by x.ordering

In Postgres 9.4 or later, this is simplest and fastest:

SELECT c.*
FROM   comments c
JOIN   unnest('{1,3,2,4}'::int[]) WITH ORDINALITY t(id, ord) USING (id)
ORDER  BY t.ord;
  • WITH ORDINALITY was introduced with in Postgres 9.4.

  • No need for a subquery, we can use the set-returning function like a table directly. (A.k.a. "table-function".)

  • A string literal to hand in the array instead of an ARRAY constructor may be easier to implement with some clients.

  • For convenience (optionally), copy the column name we are joining to (id in the example), so we can join with a short USING clause to only get a single instance of the join column in the result.

  • Works with any input type. If your key column is of type text, provide something like '{foo,bar,baz}'::text[].

Detailed explanation:

  • PostgreSQL unnest() with element number

Just because it is so difficult to find and it has to be spread: in mySQL this can be done much simpler, but I don't know if it works in other SQL.

SELECT * FROM `comments`
WHERE `comments`.`id` IN ('12','5','3','17')
ORDER BY FIELD(`comments`.`id`,'12','5','3','17')

With Postgres 9.4 this can be done a bit shorter:

select c.*
from comments c
join (
  select *
  from unnest(array[43,47,42]) with ordinality
) as x (id, ordering) on c.id = x.id
order by x.ordering;

Or a bit more compact without a derived table:

select c.*
from comments c
  join unnest(array[43,47,42]) with ordinality as x (id, ordering) 
    on c.id = x.id
order by x.ordering

Removing the need to manually assign/maintain a position to each value.

With Postgres 9.6 this can be done using array_position():

with x (id_list) as (
  values (array[42,48,43])
)
select c.*
from comments c, x
where id = any (x.id_list)
order by array_position(x.id_list, c.id);

The CTE is used so that the list of values only needs to be specified once. If that is not important this can also be written as:

select c.*
from comments c
where id in (42,48,43)
order by array_position(array[42,48,43], c.id);

I think this way is better :

SELECT * FROM "comments" WHERE ("comments"."id" IN (1,3,2,4))
    ORDER BY  id=1 DESC, id=3 DESC, id=2 DESC, id=4 DESC

Another way to do it in Postgres would be to use the idx function.

SELECT *
FROM comments
ORDER BY idx(array[1,3,2,4], comments.id)

Don't forget to create the idx function first, as described here: http://wiki.postgresql.org/wiki/Array_Index


In Postgresql:

select *
from comments
where id in (1,3,2,4)
order by position(id::text in '1,3,2,4')