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Order between destruction of global object and atexit in C++

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I wonder that can sure order between destruction of global object and atexit in C++

I have a global object and register atexit function like below:

static MyClass g_class;  void onExit() {     // do some destruction }  int main() {     atexit(onExit);      return 0; } 

I've found onExit() is invoked before MyClass::~MyClass() in Visual Studio 2012 and gcc4.7.2. Am I sure that onExit is always invoked before global object(like g_class) destruction?

I wonder global object register order and atexit register order use same order table. Or there is no relation between global object order and atexit order?

Edited : Sorry I wrote a mistake. I'm so confused while tidying example code. onExit() is invoked before ~MyClass().

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zelon Avatar asked Apr 15 '13 07:04

zelon


1 Answers

UPDATE: The OP made some confusion, and it seems VC11 does indeed behave as specified by the C++11 Standard. The following answer was written in the assumption that it did not.

Therefore, the answer to this question:

Am I sure that onExit is always invoked before global object(like g_class) destruction?

Is "Yes", as long as you are working with a fully-compliant compiler.


I've found MyClass::~MyClass() is invoked before onExit() in Visual Studio 2012.

If this is the case, then it is a bug in VC11. Per Paragraph 3.6.3/1 of the C++11 Standard:

Destructors (12.4) for initialized objects (that is, objects whose lifetime (3.8) has begun) with static storage duration are called as a result of returning from main and as a result of calling std::exit (18.5). [...]

Also, per Paragraph 3.6.3/3:

If the completion of the initialization of an object with static storage duration is sequenced before a call to std::atexit (see <cstdlib>, 18.5), the call to the function passed to std::atexit is sequenced before the call to the destructor for the object.

Therefore, in your case, onexit() should be invoked before the destructor of MyClass.

As far as I can tell, Clang 3.2 and GCC 4.8.0 are compliant in this respect, as shown in this live example.

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Andy Prowl Avatar answered Sep 23 '22 05:09

Andy Prowl