Oracle SQL pivot query

Question

I have data in a table as seen below:

MONTH VALUE

1     100
2     200
3     300
4     400
5     500
6     600

I want to write a SQL query so that result is given as below:

MONTH_JAN MONTH_FEB MONTH_MAR MONTH_APR MONTH_MAY MONTH_JUN
100       200       300       400       500       600

Answer 1

Oracle 11g and above

As of Oracle 11g, you can now use the PIVOT operator to achieve that result:

create table tq84_pivot (
  month number,
  value number
);

insert into tq84_pivot values(1, 100);
insert into tq84_pivot values(2, 200);
insert into tq84_pivot values(3, 300);
insert into tq84_pivot values(4, 400);
insert into tq84_pivot values(5, 500);
insert into tq84_pivot values(6, 600);
--
insert into tq84_pivot values(1, 400);
insert into tq84_pivot values(2, 350);
insert into tq84_pivot values(4, 150);

select 
  *
from
  tq84_pivot
pivot (
   sum (value) as sum_value for
     (month) in (1 as month_jan,
                 2 as month_feb,
                 3 as month_mar,
                 4 as month_apr,
                 5 as month_mai,
                 6 as month_jun,
                 7 as month_jul,
                 8 as month_aug,
                 9 as month_sep,
                10 as month_oct,
                11 as month_nov,
                12 as month_dec)
);

Answer 2

Oracle 9i+ supports:

SELECT SUM(CASE WHEN t.month = 1 THEN t.value ELSE 0 END) AS JAN,
       SUM(CASE WHEN t.month = 2 THEN t.value ELSE 0 END) AS FEB,
       SUM(CASE WHEN t.month = 3 THEN t.value ELSE 0 END) AS MAR,
       SUM(CASE WHEN t.month = 4 THEN t.value ELSE 0 END) AS APR,
       SUM(CASE WHEN t.month = 5 THEN t.value ELSE 0 END) AS MAY,
       SUM(CASE WHEN t.month = 6 THEN t.value ELSE 0 END) AS JUN
  FROM YOUR_TABLE t

You only list two columns -- something like this should probably be grouped by year.

There is ANSI PIVOT (and UNPIVOT) syntax, but Oracle didn't support it until 11g. Prior to 9i, you'd have to replace the CASE statements with Oracle specific DECODE.