I have a oracle table with record count of 99896618.
I need to fetch small chunk of data(lets say 100 records) to show it on a web page,(In web world we call it paging). Currently I am using the following query to accomplish that however users are not satisfied with the performance.
SELECT * FROM (select rownum rnum,f.* from findings f where rownum<90000100 )
WHERE rnum > 90000000
Currently it is taking 1 min 22 seconds to get the results. Is there anyway to make it better. I am certainly open for any type of suggestions including modifying the table structure or like adding indexes.
(Just FYI,I am using ASP.NET as server side web technology and ADO.NET as data access layer and silverlight for client side presentation)
Your query will need to count off the first 90M
records to get the next 100
, so there is hardly a room for improvement.
I don't see an ORDER BY
clause in your subquery, but probably you have it. In this case, you may want to create an index on it.
And a question: do your users really click through 900K
pages before complaining about performance?
Update:
If you need the latest page, you need to rewrite your ORDER BY
column in descending order:
SELECT *
FROM (
SELECT rownum rnum, f.*
FROM findings f
ORDER BY
record_ordering_column DESC
)
WHERE rnum > 900
AND rownum <= 100
and create an index on record_ordering_column
Note that I mix rownum
's from the nested queries to improve performance.
See this article in my blog for more detail:
From one of your comments:
most of the time(around 95% of the time) users are interested in the last(latest) records
In that case, why not show the records in reverse order so that 95% of the time the users are interested in page 1 rather than page 900,000?
If they really then want to see "page 900,000", that means they are interested in data from a long time ago, so allow them to filter data by e.g. date range. Just paging through 100 million rows without any filtering is never going to be performant.
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