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how can I select Julian day of year in Oracle database?
I tried: select to_char(sysdate, 'J') from dual; Which gives me the number of days since January 1, 4712 BC. But I would need the number of days since 1.1. of current year.
436
Today's date is 23-Aug-2022 (UTC). Today's Julian Date is 22235 .
The first two digits are the last numbers of the year and the three digits after the hyphen are the day of that year. So, for instance, a Julian date of 21-001 represents the first day of the year 2021, or January 1, 2021, while a Julian date of 22-165 represents the 165th day of the year 2022 or June 14, 2022.
An Oracle Julian date is a 7 digit number, representing the number of days elapsed since December 31st, 4712 B.C. For instance, 2451367 represents July 7, 1999.
Multiply the number of non-leap years by 365, and the number of leap years by 366. Add the two totals together for a total number of days in all years.
SELECT TO_CHAR(SYSDATE, 'DDD') from DUAL;
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