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If I want to make a method in my interface optional, is it possible to do that ? How ?
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Use the Partial utility type to make all of the properties in a type optional, e.g. const emp: Partial<Employee> = {}; . The Partial utility type constructs a new type with all properties of the provided type set to optional. Copied!
No. Consider logs (such as error logs, audit logs and journals for recoverable data objects). They are natural append-only sequences, that support all of the List operations except for remove and set (replace). They require a new core interface, and a new iterator.
To make all of the properties of a type optional except one, use an interface to extend the type passing it to the Partial utility type, e.g. interface OptionalExceptSalary extends Partial<Employee> {} and override the specific property setting it to required.
If you want to set the properties of an interface to have a default value of undefined , you can simply make the properties optional. Copied!
Specify in the Javadoc that implementing classes may choose to throw UnsupportedOperationException.
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