I am solving a programming problem which is stuck at calculating nCr
efficiently and at the same time avoiding overflows. I have made the following trivial simplification but am just curious about if there are any more sophisticated simplifications available out there.
(n)!/(n-k)!*k! = n*(n-1)*.....*(max(n-k+1, k))/(min(n-k, k-1))
Can there be any more simplification possible considering different cases for k as even or odd, just suggesting a way.
Any comment is appreciated.
I found an interesting solution here: http://blog.plover.com/math/choose.html
unsigned choose(unsigned n, unsigned k) {
unsigned r = 1;
unsigned d;
if (k > n) return 0;
for (d=1; d <= k; d++) {
r *= n--;
r /= d;
}
return r;
}
This avoids overflows (or at least limits the problem) by performing multiplication and division alternatively.
E.g. for n = 8
, k = 4
:
result = 1;
result *= 8;
result /= 1;
result *= 7;
result /= 2;
result *= 6;
result /= 3;
result *= 5;
result /= 4;
done
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