== operator overloading when object is boxed

Question

The output of the below code is as following:

not equal
equal

Note the difference in type of x and xx and that == operator overload is only executed in the second case and not in the first.

Is there a way I can overload the == operator so that its always executed when a comparison is done on between MyDataObejct instances.

Edit 1:# here i want to override the == operator on MyDataClass , I am not sure how I can do it so that case1 also executes overloaded == implementation.

class Program {
    static void Main(string[] args) {
        // CASE 1
        Object x = new MyDataClass();
        Object y = new MyDataClass();
        if ( x == y ) {
            Console.WriteLine("equal");
        } else {
            Console.WriteLine("not equal");
        }

        // CASE 2 
        MyDataClass xx = new MyDataClass();
        MyDataClass yy = new MyDataClass();
        if (xx == yy) {
            Console.WriteLine("equal");
        } else {
            Console.WriteLine("not equal");
        }
    }
}

public class MyDataClass {
    private int x = 5;

    public static bool operator ==(MyDataClass a, MyDataClass b) {
        return a.x == b.x;
    }

    public static bool operator !=(MyDataClass a, MyDataClass b) {
        return !(a == b);
    }
}

Answer 1

No, basically. == uses static analysis, so will use the object ==. It sounds like you need to use object.Equals(x,y) instead (or x.Equals(y) if you know that neither is null), which uses polymorphism.