openpyxl - adjust column width size

Question

I have following script which is converting a CSV file to an XLSX file, but my column size is very narrow. Each time I have to drag them with mouse to read data. Does anybody know how to set column width in openpyxl?

Here is the code I am using.

#!/usr/bin/python2.6 import csv from openpyxl import Workbook from openpyxl.cell import get_column_letter  f = open('users_info_cvs.txt', "rU")  csv.register_dialect('colons', delimiter=':')  reader = csv.reader(f, dialect='colons')  wb = Workbook() dest_filename = r"account_info.xlsx"  ws = wb.worksheets[0] ws.title = "Users Account Information"  for row_index, row in enumerate(reader):     for column_index, cell in enumerate(row):         column_letter = get_column_letter((column_index + 1))         ws.cell('%s%s'%(column_letter, (row_index + 1))).value = cell  wb.save(filename = dest_filename) 

Answer 1

You could estimate (or use a mono width font) to achieve this. Let's assume data is a nested array like

[['a1','a2'],['b1','b2']] 

We can get the max characters in each column. Then set the width to that. Width is exactly the width of a monospace font (if not changing other styles at least). Even if you use a variable width font it is a decent estimation. This will not work with formulas.

from openpyxl.utils import get_column_letter  column_widths = [] for row in data:     for i, cell in enumerate(row):         if len(column_widths) > i:             if len(cell) > column_widths[i]:                 column_widths[i] = len(cell)         else:             column_widths += [len(cell)]      for i, column_width in enumerate(column_widths,1):  # ,1 to start at 1     worksheet.column_dimensions[get_column_letter(i)].width = column_width 

A bit of a hack but your reports will be more readable.