Open URL in browser even though my app registered an intent-filter for it

Question

My app registers an intent filter for certain URLs because it can handle the data from those URLs.

However, inside the app I would like to provide a button to open such an URL in the browser. That is, open it in the default browser if one is set, otherwise provide a chooser - just like normal.

Now when my app is set as default for those URLs and I press the button, naturally I just get the same activity in my app again and again and again.

Any ideas?

Answer 1

What I ended up doing is:

Intent i = new Intent(Intent.ACTION_VIEW,
        Uri.parse("https://website.com/entries/" + entry_id));

// Check what is the default app to handle these entry URLs

ResolveInfo defaultResolution = getPackageManager().resolveActivity(i,
        PackageManager.MATCH_DEFAULT_ONLY);

// If this app is the default app for entry URLs, use the browser instead

if (defaultResolution.activityInfo.packageName.equals(getPackageName())) {

    Intent browseIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://"));

    ResolveInfo browseResolution = getPackageManager().resolveActivity(browseIntent,
            PackageManager.MATCH_DEFAULT_ONLY);

    i.setComponent(new ComponentName(
            browseResolution.activityInfo.applicationInfo.packageName,
            browseResolution.activityInfo.name));

}

startActivity(i);

Answer 2

You can do one of two things:

1. Create an explicit Intent for the browser if you know that one (Chrome, for example) will be installed on the device

2. Create a chooser by using

   Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse("google.com")); Intent chooserIntent = Intent.createChooser(i, "Title for chooser"); startActivity(chooserIntent);

You can read more about createChooser here