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How do you show the Open File Dialog on Windows using just straight C++ and the Windows API? I'm trying to load an image to display on the screen.
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Creating a OpenFileDialog We can create an OpenFileDialog control using a Forms designer at design-time or using the OpenFileDialog class in code at run-time (also known as dynamically). Unlike other Windows Forms controls, an OpenFileDialog does not have and not need visual properties like others.
Detailed Solution. CTRL + F12 help to open dialogue box.
OpenFileDialog component opens the Windows dialog box for browsing and selecting files. To open and read the selected files, you can use the OpenFileDialog. OpenFile method, or create an instance of the System.
Use a Keyboard Shortcut The fastest way to access most Windows software programs is through keyboard shortcuts. To quickly access the Run command dialog box, simply press the Windows key + R.
You want the common file dialog API, specifically GetOpenFileName - http://msdn.microsoft.com/en-us/library/windows/desktop/ms646927(v=vs.85).aspx
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