Open cmd, change directory and execute command

Question

I'm trying to write a simple batch file to initialize some tools I need on windows startup. This is what I've at the moment:

@echo off
start /d "C:\Program Files\Sublime Text 3" sublime_text.exe
start cmd.exe /k cd /d "D:xampp/htdocs/webshop"

What I'd like to do is to execute the command compass watch once the directory has changed.

I tried start cmd.exe /k cd /d "D:xampp/htdocs/webshop" /k "compass watch" but it refers to the cd command then and thus throws me an error message (The system cannot find the path specified).

Any suggestions?

EDIT

To clarify what I need:

1. Open console
2. cd to the relevant directory
3. Execute the command compass watch (in that directory)

I normally do this by manually typing in the commands into the console as listed above. What I'd like to have is a simple .bat file that does exactly that with just one click.

Answer 1

You state in the comments that you don't need a separate interpreter. In which case I believe you can do it like this:

@echo off
start /d "C:\Program Files\Sublime Text 3" sublime_text.exe
start /d D:\xampp\htdocs\webshop compass watch