Open a Google Drive File Content URI after using KitKat Storage Access Framework

Question

I am using the Storage Access Framework for android 4.4 and opening the file picker.

Everything works except when choosing a file from Google Drive, I can only figure out how to open it as an input stream, but I would like to get a java File object.

The content uri that's being returned looks something like this: content://com.google.android.apps.docs.storage/document/acc%3D4%3Bdoc%3D2279

Other questions that are similar but do not have a working solution which allows me to get the filename, filesize and contents:

• Get real path from URI, Android KitKat new storage access framework
• Android Gallery on KitKat returns different Uri for Intent.ACTION_GET_CONTENT

I've also looked into Paul Burke's FileChooser ( https://github.com/iPaulPro/aFileChooser) and this is the most common question on the issue's list.

How can I get a file from that content uri?

My current workaround is to write out a temporary file from an inputstream.

Thanks!

Answer 1

Ok. I found that the right way is to use the input stream from the other posts in conjunction with some data from the contentresolver.

For reference here are the hard to find android docs: https://developer.android.com/training/secure-file-sharing/retrieve-info.html

The relevant code to get mimetype, filename, and filesize:

Uri returnUri = returnIntent.getData(); String mimeType = getContentResolver().getType(returnUri); Cursor returnCursor =         getContentResolver().query(returnUri, null, null, null, null); int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME); int sizeIndex = returnCursor.getColumnIndex(OpenableColumns.SIZE); returnCursor.moveToFirst(); TextView nameView = (TextView) findViewById(R.id.filename_text); TextView sizeView = (TextView) findViewById(R.id.filesize_text); nameView.setText(returnCursor.getString(nameIndex)); sizeView.setText(Long.toString(returnCursor.getLong(sizeIndex))); 

And to get the file contents:

getContentResolver().openInputStream(uri) 

Hope this helps someone else.

Answer 2

Adding to @Keith Entzeroth answer , after getting fileName, fileSize and Input Stream , this is way to get the file

 public static File getFile(final Context context, final Uri uri) {         Log.e(TAG,"inside getFile==");         ContentResolver contentResolver = context.getContentResolver();         try {             String mimeType = contentResolver.getType(uri);             Cursor returnCursor =                     contentResolver.query(uri, null, null, null, null);             int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);             int sizeIndex = returnCursor.getColumnIndex(OpenableColumns.SIZE);             returnCursor.moveToFirst();             String fileName = returnCursor.getString(nameIndex);             String fileSize = Long.toString(returnCursor.getLong(sizeIndex));             InputStream inputStream =  contentResolver.openInputStream(uri);               File tempFile = File.createTempFile(fileName, "");             tempFile.deleteOnExit();             FileOutputStream out = new FileOutputStream(tempFile);             IOUtils.copyStream(inputStream,out);             return tempFile;            }catch (Exception e){             e.printStackTrace();             return null;         }     }