In my project I have a table Translation
that can have translations for any model. To achieve this, the table has two fields: Model
and ModelId
. The Model
property holds an integer indicating the type of the model and the ModelId
has the id of this model.
So, for example: the Product
table has modeltype id 1
. To get all translations for a product with id 317
, I search for translations with Model=1 AND ModelId=317
.
Now I would like to create this relation in Entity Framework Core. All my models inherit from the class BaseModel
that has a property ModelType
holding the id of the model type. This field is not mapped, so it is not available in the database.
I have tried to create the relation using fluent api, but it doesn't allow me to specify more columns to filter on.
modelBuilder.Entity<BaseModel>()
.HasMany<Translation>(bm => bm.Translations)
// Extra filters
Is there any way to create this relation without having to manually create a join for every query that requires translations?
The easiest way to configure a one-to-many relationship is by convention. EF Core will create a relationship if an entity contains a navigation property. Therefore, the minimum required for a relationship is the presence of a navigation property in the principal entity: public class Author.
Many-to-many relationships require a collection navigation property on both sides. They will be discovered by convention like other types of relationships. The way this relationship is implemented in the database is by a join table that contains foreign keys to both Post and Tag .
You can create such a relationship by defining a third table, called a junction table, whose primary key consists of the foreign keys from both table A and table B.
Since modelBuilder.Entity<BaseModel>()
will use TPH
inheritance approach, I assume you are not using EF code first approach for database creation and you are using it to map your models to an existing database. Then you can try something like this:
Models:
public class Translation
{
public int Id { get; set; }
public int Model { get; set; }
public int ModelId { get; set; }
}
public class BaseModel
{
public BaseModel(int modelType)
{
ModelType = modelType;
}
public int Id { get; set; }
public int ModelType { get; set; }
public ICollection<Translation> Translations { get; set; }// only for internal use
public IEnumerable<Translation> ModelTypeTranslations
{
get
{
return this.Translations.Where(t => t.Model == this.ModelType);
}
}
}
public class SomeModel : BaseModel
{
public SomeModel() : base(1) { }
public int SomeProperty { get; set; }
}
public class AnotherModel : BaseModel
{
public AnotherModel() : base(2) { }
public int AnotherProperty { get; set; }
}
DbContext:
public class MyDbContext: DbContext
{
...
public DbSet<Translation> Translations { get; set; }
public DbSet<SomeModel> SomeModels { get; set; }
public DbSet<AnotherModel> AnotherModels { get; set; }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
...
modelBuilder.Entity<Translation>().HasKey(e => e.Id);
var baseModelTypes = typeof(BaseModel).Assembly.GetExportedTypes()
.Where(t => typeof(BaseModel).IsAssignableFrom(t) && t != typeof(BaseModel)).ToList();
foreach (var type in baseModelTypes)
{
modelBuilder.Entity<Translation>().HasOne(type).WithMany(nameof(BaseModel.Translations)).HasForeignKey(nameof(Translation.ModelId));
modelBuilder.Entity(type).Ignore(nameof(BaseModel.ModelType));
modelBuilder.Entity(type).Ignore(nameof(BaseModel.ModelTypeTranslations));
modelBuilder.Entity(type).HasKey(nameof(BaseModel.Id));
}
}
}
As you can see you can use ModelTypeTranslations
to get Translations only for current model type.
I should note this approach may have performance issues since it filters Translations
by ModelType
only in memory. Also I tried to avoid filtering in memory by using lazy loading
but I got some exception even if I just installed that package without invoking optionsBuilder.UseLazyLoadingProxies()
. I hope it will be fixed in the next releases.
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